![]() ![]() Now you have data colored the way that you want, but now your data is linked to the colorbar. data = rand(10) ĬontourLevels = Ĭontour(data, contourLevels, 'LineWidth', 2) So now we can create a single contour plot for all levels that you want to display with some pseudo data just with the difference that we'll set the figure's colormap to be the custom one defined above. ![]() So for your example this colormap (based on your data above) would look something like this. ![]() The number of colors in the colormap will determine the color resolution of the resulting images. To use a different number of colors, change the colormap with the cmapnamed argument. Rather than creating a bunch of separate contour objects (that are no longer tied to the colormap/colorbar as you've found) it is easier to construct a custom colormap to use that corresponds to the colors you want. By default, pcolor()and pcolormesh()use the number of values in the colormap to map the data from the numerical values of the scalar in argument z. Any idea?īy default, the contour plot uses the current colormap of the figure to decide what color the contour lines are going to be. But the colorbar doesn't change accordingly. The color of lines changed, the level shown is as expected. Hold on contour(f,, 'linewidth', 2, 'linecolor','r') Sequential: change in lightness and often saturation of color incrementally, often using a single hue should be used for representing information that has ordering. Hold on contour(f,, 'linewidth', 2, 'linecolor','g') Hold on contour(f,, 'linewidth', 2, 'linecolor','b') Hold on contour(f,, 'linewidth', 2, 'linecolor','k') Hold on contour(f,, 'linewidth', 2, 'linecolor','y') Hold on contour(f,, 'linewidth', 2, 'linecolor','c') Updated: I find a way to do the trick hold on contour(f,, 'linewidth', 2, 'linecolor','m') Secondly, it doesn't use the color I specify, it seems that it doesn't contain any patch objects from that handle. Display X using the image function and set the colormap to map. This code plots the line not exactly on level -60 -30 -20 0 20 30 50 and 60 but something close as well. Change Colormap for Figure with Image Load the spine data set that returns the image X and its associated colormap map. I found some solution is trying to look for the patch object and define the facecolor from there for each contour line. The syntax for its use is y gray Example Here is an example of an image displayed with the gray colormap which results in the following image Page Last Updated on: Sunday, October 25, 2009, 12:19:06 AM (CEST). I am trying to plot a contour (not contourf) of specific level of some 3D data in matlab. GRAY Gray Colormap Section: Handle-Based Graphics Usage Returns a gray colormap. ![]() Here is how you might do that with your situation aLetter = max(aLetter(:)) - aLetter % invert image: now white = close to zeroĪLetter = aLetter - min(aLetter(:)) % make the smallest value zeroĪLetter(aLetter 90% of your image is "white", you could determine the correct threshold by sorting the pixels and finding the threshold dynamically - as I mentioned in my comment in the code "play with it" until you find something that works in your situation.I think it is not a fresh question but I didn't find a concrete solution or the solution I found so far doesn't solve my problem. upsample the image in the bounding box to a multiple of 8.sum along row and column, find non-zero pixels.limits is a two-element vector of the form cmin cmax. set things that are "not text" to zero - anything below a threshold Set colormap limits (Renamed from caxis in R2022a) collapse all in page Syntax clim (limits) clim ('auto') clim ('manual') clim (target, ) lims clim Description example clim (limits) sets the colormap limits for the current axes.make sure that "text" is the highest value in the image.Find the approximate 'bounding box' of the letter:.You need several steps to achieve what you want (updated in the light of observation that I had white and black flipped…): ![]()
0 Comments
Leave a Reply. |